1 Answer

Zilongqiu · Answer 1 · 2021-02-06T05:17:52+0000

Answer:

Standard form:
12x+3y-2=0

A = 12, B = 3 and C = -2

Explanation:

Given:

The equation:

$y= -4x + \frac{2}3$

To find:

The standard form of given equation and find A, B and C.

Solution:

First of all, let us write the standard form of an equation.

Standard form of an equation is represented as:

Ax+By+C=0

A is the coefficient of x and can be positive or negative.

B is the coefficient of y and can be positive or negative.

C can also be positive or negative.

Now, let us consider the given equation:

$y= -4x + \frac{2}3$

Multiplying the whole equation with 3 first:

$3 * y= 3 * -4x + 3 * \frac{2}3\\\Rightarrow 3y=-12x+2$

Now, let us take all the terms on one side:

$\Rightarrow 3y+12x-2=0\\\Rightarrow 12x+3y-2=0$

Now, let us compare with
Ax+By+C=0 .

So, A = 12, B = 3 and C = -2

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