Question

A card is drawn from a well shuffled deck of 52 cards. What is the probability of drawing an ace or a 9? Round to nearest thousandth

Answer 1

0.154

Explanation:

We want to find the probability of drawing an ace or a 9.

P(ace or 9)= aces and 9s / total cards

There are 4 aces and 4 9s in a standard deck of cards. This means there is a total of 8 aces and 9s.

In a standard deck of cards, there is a total of 52 cards.

P(ace or 9)= aces and 9s / total

aces and 9s= 8

total= 52

P(ace or 9)= 8/52

This fraction can be simplified. Both the numerator and denominator can be evenly divided by 4.

P(ace or 9)= (8/4) / (52/4)

P(ace or 9)= 2/13

P(ace or 9)= 0.153846153846154

Round to the nearest thousandth. The 8 in the ten thousandth place tell sus to round the 3 up to a 4.

P(ace or 9) = 0.154

The probability of drawing an ace or 9 is 0.154

Answer 2

.154

Explanation:

There are 52 cards

There are 4 aces and 4 9's for a total of 8 cars

P (ace or 9) = number of aces or 9's / total

= 8/52 = 2 /13 =.153846154

To the nearest thousandth

= .154