Answer:
![Area = 24.8 cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/l38mzw3pixrctbg3k41kxf28l48wp8hryb.png)
Explanation:
Given
![PQ = 4.9cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/3g48hav8f05v1nf7g3vnkp80mk5spg9s7o.png)
![RQ = 11 cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/f3f6rj2fvao6h4gu8n3sao1iuuelq1f26w.png)
![<Q = 113\ degrees](https://img.qammunity.org/2021/formulas/mathematics/high-school/ezswq0f5m5fm7cdi43p9dj00ee9fl5guiz.png)
Required
Find the area of the triangle
When presented with a triangle where two sides are known and an angle between the two sides; The area is solved as follows;
![Area = (1)/(2)ABSinC](https://img.qammunity.org/2021/formulas/mathematics/high-school/hnvgq4y3igfryyqv4azue7masi6brscx0n.png)
Where A and B are the two known sides and C is the angle between A and B
Having said that;
The area of the triangle is calculated as thus;
![Area = (1)/(2) * RQ * PQ * SinQ](https://img.qammunity.org/2021/formulas/mathematics/high-school/34f7tm90w8nej13pbuzwymylevl8y0d8aj.png)
![Area = (1)/(2) * 11 * 4.9 * Sin113](https://img.qammunity.org/2021/formulas/mathematics/high-school/rjejjmyjb2nw5r7bcwcyk2ctme1w13mhnj.png)
![Sin113 = 0.9205](https://img.qammunity.org/2021/formulas/mathematics/high-school/ukt5siyopkm7meexqtx4u4pamd8hizlqfl.png)
Hence, the equation becomes
![Area = (1)/(2) * 11 * 4.9 * 0.9205](https://img.qammunity.org/2021/formulas/mathematics/high-school/q9cnpwtku5xjtv3wq2edqkfuz3pesvblgg.png)
![Area = (11 * 4.9 * 0.9205)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/acuyn3waqjtwby13d8ujmy6z4d3zqjg85t.png)
![Area = (49.6152)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/rsdsvqug00hr0awzabu2frzzw7xlnu2434.png)
![Area = 24.8076](https://img.qammunity.org/2021/formulas/mathematics/high-school/o3o1dqqjk90tswembvhgsjcv7wco42f7sr.png)
--- Approximated