Question

A wire carrying a 35.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.55 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet

Answer 1

7.65 T

Step-by-step explanation:

From the question,

Using,

F = BILsinФ......................... Equation 1

Where F = Force, B = magnetic field strength, I = current, L = Length, Ф = Angle.

Make B the subject of the equation

B = F/ILsinФ........................Equation 2

Given: F = 2.55 N, I = 32 A, L = 3.00 cm = 0.03 m, Ф = 90° (perpendicular)

Substitute into equation 2

B = 2.55/(32×0.03×sin90°)

B = 2.55/0.96

B = 7.65 T