5x(3x + 2) - x(5x - 2) required expression.
Explanation:
I get there are 2 rectangles in figure.
How can I get the area of shaded region? What if, I subtract the area of inner rectangle from outer rectangle. Ya It will surely work (⌒o⌒).
Now,
Area of outer rectangle =
![\sf length * breadth](https://img.qammunity.org/2021/formulas/mathematics/high-school/efdmd2h4eqqqtz5z1z6einxkxhdx81j7oe.png)
![5x * (3x + 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sbj0pkqxlupxfn5qfvno7umtnxqy7mjbaa.png)
![5x(3x + 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3gvf10bndgbnzuqbcwleiuyep0j2vl5tsd.png)
Again,
Area of inner rectangle =
![\sf length * breadth](https://img.qammunity.org/2021/formulas/mathematics/high-school/efdmd2h4eqqqtz5z1z6einxkxhdx81j7oe.png)
![=x * (5x - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nenv5ebb3mzy49hzbm2iw4g1c0hj0riwob.png)
![=x(5x - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/j8rcos6e4jt8xm26lnjkhoyx68318kzjr6.png)
![\sf Area \:of \:Shaded\: region = \: Area_(\:outer)-Area_(\:inner)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9u2apngua2hrlznci07m4hfc2lje36ywv1.png)
![\sf \: 5x(3x + 2) - x(5x - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ds3oxzlsrkz374hloibv84fj2xydtn0yj4.png)
If We simplify further then,
= 15x² + 10x - 5x² + 2x
= 10x² + 12x
Area of shaded region is 10x² + 12x in a simple way.