Question

A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reaches to a region in space with magnetic field of 0.05 (T) and experience a force of 8 (N) exerted by the magnetic field.

A- What is the angle between velocity of particle and magnetic field direction?
B- What is acceleration of charged particle while experiencing the force?

Answer 1

Step-by-step explanation:

A ) Let the angle be θ between magnetic field and velocity of charged particle

Force created on charged particle F

= Bqv sinθ, B is magnetic field , q is charge , v is velocity of charged particle

F = .05 x 2 x 10⁻⁶ x 10⁸ x sinθ

8 = 10 sinθ

sinθ = .8

θ = 53°.

B )

acceleration = force / mass

= 8 / 10⁻²⁰

= 8 x 10²⁰ m / s²