Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-8, -6), B(-3,-6), C(-3, -4), and D(-8, -4). Given these coordinates, what is the length of side AB of this rectangle?

Answer 1

Explanation:

Distance =
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}`

A(-8,-6) ; B(-3,-6)

`AB= \sqrt{(-3-[-8])^(2)+(-6-[-6])^(2)}\\\\=\sqrt{(-3+8)^(2)+(-6+6)^(2)}\\\\=\sqrt{(5)^(2)+ 0}\\\\= 5 units`