Question

What are the coordinates of the vertex of the function f(x)=x2+ 10x-3?

O (-5. -28)
(-5, 28)
O (5,-28)
(5.28)​

Answer 1

(-5,-28)

Explanation:

Use the vertex form y=a(x-h)^2

a=1

h=-5

k=-28

vertex=(h,k)

Answer 2

Answer: A. (-5, -28)

Explanation:

f(x) = x² + 10x - 3

a=1 b=10

The axis of symmetry is the x-coordinate of the vertex:

`AOS: x=(-b)/(2a)\quad =(-(10))/(2(1))=-5`

Input x = -5 into the original equation to find the y-coordinate of the vertex:

f(-5) = (-5)² + 10(-5) - 3

= 25 -50 -3

= -28

x, y coordinate of the vertex is: (-5, -28)