Question

The value of y varies inversely as the square of x, and y = 9, when x = 4.

Find the value of x when y = 1. Do not include "=" in your answer.​

Answer 1

±2

Explanation:

Answer 2

The answer is

12

Explanation:

The above variation is written as

`y = \frac{k}{ {x}^(2) }`

where k is the constant of variation

when y = 9

x = 4

We have

k = yx²

k = 9(4)²

k = 9 × 16

k = 144

So the formula for the variation is

`y = \frac{144}{ {x}^(2) }`

when y = 1

`1 = \frac{144}{ {x}^(2) }`

Cross multiply

x² = 144

Find the square root of both sides

x = √144

x = 12

Hope this helps you.