Answer:
15 and 4
Explanation:
Let the first integer be x and the second integer be y. If the first integer is 7 more than 2 times another, then x = 7+2y
The two integers will be y and 7+2y. If the product of both integers is 60, then;
y(7+2y) = 60
7y + 2y² = 60
2y² + 7y -60 = 0
2y²-8y+15y-60 = 0
2y(y-4)+15(y-4) = 0
(2y+15)(y-4) = 0
2y+15= 0 and y-4 = 0
2y = -15 and y = 4
y = -15/2 and 4
Taking the positive integer, y = 4
To get the other integer, we will substitute y = 4 into the equation x = 7+2y;
x = 7+2(4)
x = 7+8
x = 15
Hence the two integrs are 15 and 4