Answer:
a. p`± z₀.₀₂₅
b.0.6 ± 1.96
c. { -1.96 ≤ p`± z₀.₀₂₅
≥ 1.96} = 0.95
Explanation:
Here the total number of trials is n= 1000
The number of successes is p` = 600/1000 = 0.6. The q` is 1 - p`= 1- 0.6 = 0.4
The degree of confidence is 95 % therefore z₀.₀₂₅ = 1.96 ( α/2 = 0.025)
a. The formula used will be
p`± z₀.₀₂₅
( z with the base alpha by 2 (α/2 = 0.025))
b. Putting the values
0.6 ± 1.96
c. Confidence Interval in Interval Notation.
{ -1.96 ≤ p`± z₀.₀₂₅
≥ 1.96} = 0.95
{ -z( base alpha by 2) ≤ p`± z₀.₀₂₅
≥ z( base alpha by 2) } = 1- α