Answer:
The p-value is 0.809.
Explanation:
In this case we need to perform a significance test for the standard deviation.
The hypothesis is defined as follows:
H₀: σ₀ = 4 vs. Hₐ: σ₀ ≤ 4
The information provided is:
n = 9
s = 3
Compute the Chi-square test statistic as follows:
![\chi^(2)=((n-1)s^(2))/(\sigma_(0)^(2))](https://img.qammunity.org/2021/formulas/mathematics/college/ew35ybpojbis4ku3axw8mxnl3bet3763o9.png)
![=((9-1)\cdot (3)^(2))/((4)^(2))\\\\=(8* 9)/(16)\\\\=4.5](https://img.qammunity.org/2021/formulas/mathematics/college/nunafiqyweu4gjnk5ahj1pay5sb3li7nxz.png)
The test statistic value is 4.5.
The degrees of freedom is:
df = n - 1
= 9 - 1
= 8
Compute the p-value as follows:
![p-value=P(\chi^(2)_(9)>4.5)=0.809](https://img.qammunity.org/2021/formulas/mathematics/college/bfjd6jx9bn20pbg5hkacwrzl3bs4mtuhyk.png)
*Use a Chi-square table.
Thus, the p-value is 0.809.