Answer:
A) 3 interactions
B) 2.78 m/s
C) 2.78 m/s
D) 0 m/s
Step-by-step explanation:
Given Data :
plastic buttons ( 2 ) = 2.0 g each
charge on each plastic buttons = +65 nC
A) The interactions that have potential energy can be expressed as
V net = v1 + v2 + v3
V net = 0 +

hence the total interactions is (3)
B) The final speed of the left 2.0 g plastic button
U =
![(9*10^9* 10^-18)/(0.02) [ 65*250 + 65*250 + (65*65)/2 ]](https://img.qammunity.org/2021/formulas/physics/college/nge6sxww9591dmk096s8yupotjryvgqcsj.png)
U = 0.0155 J
also U =

U = mv^2 = 0.0155 J
therefore ; v =
= 2.78 m/s
C) final speed of the right 2.0 g plastic button = Final speed of the right 2.0 g plastic button
v = 2.78 m/s
D) The final speed of the 5.0 g plastic button
= 0 m/s