Answer:
80 deg
Explanation:
Theorem:
The measure of an inscribed angle is half the measure of the intercepted arc.
m<EFG = (1/2)m(arc)EG
40 deg = (1/2)m(arc)EG
m(arc)EG = 2 * 40 deg
m(arc)EG = 80 deg
80 = EG
Inscribed Angle = 1/2 Intercepted Arc
40 = 1/2 EG
Multiply each side by 2
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