Answer:
Distance travel by Drew = 1,315.21 feet (Approx)
Explanation:
Given:
Total block in north = 3
Total block in west = 3
1 block = 310 feet
Find:
Distance travel by Drew
Computation:
Total distance in north = 3 × 310 = 930 feet
Total distance in west = 3 × 310 = 930 feet
Distance travel by Drew = √Total distance in north² + Total distance in west²
Distance travel by Drew = √930² + 930²
Distance travel by Drew = √864,900 + 864,900
Distance travel by Drew = √1,729,800
Distance travel by Drew = 1,315.21 feet (Approx)