Answer:
The answer to this question can be defined as follows:
Explanation:
In the question equation is missing so, the equation and its solution can be defined as follows:
![B={b_1,b_2}\\\\b_1= \left[\begin{array}{c}5&5\end{array}\right] \ \ \ \ \b_2= \left[\begin{array}{c}2&-5\end{array}\right] \ \ \ \ \x= \left[\begin{array}{c}-7&-35\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/bmdcqlnhjk55pv4xbcsufguurk1cj9m4x9.png)
![\left[\begin{array}{c}a&c\end{array}\right] =?](https://img.qammunity.org/2021/formulas/mathematics/college/1svo048evjcv634hn8atoftorxf0vq6vba.png)
![\to \left[\begin{array}{c}-7&-35\end{array}\right]= a\left[\begin{array}{c}5&5\end{array}\right]+c \left[\begin{array}{c}2&-5\end{array}\right] \\](https://img.qammunity.org/2021/formulas/mathematics/college/lgzo5nd6mm7l4xn54d95ihs4nwfc796aos.png)
![\to \left[\begin{array}{c}-7&-35\end{array}\right]= \left[\begin{array}{c}5a+2c&5a-5c\end{array}\right]\\\\\to 5a+2c=-7....(1)\\\\\to 5a-5c=-35....(2)\\\\](https://img.qammunity.org/2021/formulas/mathematics/college/e4xeeip32m9g8ndhho2w2pt0ap0pzws1dh.png)
subtract equation 1 from equation 2:

put the value of c in equation 1

coordinate value is [-3,4].