Question

A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What

will the volume of the gas be at a pressure of 0.954 atmospheres, if the temperature
remains constant?
Select one:
O a. 23.6
Ob. 0.0102
O c. 88.8
O d. 0.0113

Answer 1

the answer should be 23.6

Answer 2

a. 23.6

Step-by-step explanation:

`P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\(P_1V_1)/(P_2) = (P_2V_2)/(P_2) \\ \\V_2 =(P_1V_1)/(P_2) \\V_2 = (0.492*45.8)/(0.954)\\ \\V_2 = (22.5336)/(0.954) \\\\V_2 = 23.620\\\\V_2 = 23.6`