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Enter an equation for the line of symmetry for the function f(x) = 2(x-5)^2 + 8.

User Yanir Mor
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so let's notice that, the equation is f(x) in x-terms, meaning the variable "x" is the independent and thus the parabola is a vertical parabola. Also let's notice that the equation is already in vertex form, keeping in mind that the axis of symmetry occurs for a vertical parabola at the x-coordinate.


~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{

User Muhamed Riyas M
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