Question

A capacitor that is initially uncharged is connected in series with a resistor and an emf source with E=110V and negligible internal resistance. Just after the circuit is completed, the current trhough the resistor is 6.5*10^-5A. the time constant for the circuit is 4.8s.

1) What is the resistance of the resistor?
2) What is the capacitance of the capacitor?

Answer 1

1

`R = 1.692*10^(6) \Omega`

2

`C = 2.837 *10^(-6) \ F`

Step-by-step explanation:

From the question we are told that

The voltage is
`E = 110 \ V`

The current is
`I = 6.5 *10^(-5) \ A`

The time constant is
`\tau = 4.8 \ s`

The resistance of resistor is mathematically evaluated as

`R = (E)/(I)`

substituting values

`R = ( 110 )/( 6.5*10^(-5))`

`R = 1.692*10^(6) \Omega`

The capacitance of the capacitor is mathematically represented as

`C = (\tau)/(R)`

substituting values

`C = ( 4.8)/( 1.692*10^(6))`

`C = 2.837 *10^(-6) \ F`