Question

The table below shows some inputs and outputs of the invertible function f ff with domain all real numbers.

x: -14,-7,-12,9,10,-2
f(x):11,-12,5,1,-2,13

f^-1(1)+f(−14): ?
f^-1(−2): ?
PLEASE HELP!

Answer 1

Answer:
`f^(-1)(1)+f(-14)=20`

`f^(-1)(-2)=10`

Explanation:

The given table :

x: -14,-7,-12,9,10,-2

f(x):11,-12,5,1,-2,13

Since f is invertible ( given) , then
`f^(-1)(x)` exists.

Now , from table
`f^(-1)(1)=9` [ x= 9 corresponding to f(x) =1]

`f(-14)=11` [ f(x) = 11 corresponding to x=-14]

then,
`f^(-1)(1)+f(-14)=9+11=20`

So,
`f^(-1)(1)+f(-14)=20`

Also, x= 10 corresponding to f(x) =-2, then

`f^(-1)(-2)=10`