Answer:
Option A. 7.98 L.
Step-by-step explanation:
The following data were obtained from the question:
Initial volume (V1) = 8 L
Initial temperature (T1) = 9.9 °C
Final temperature (T2) = 9.3 °C
Final volume (V2) =..?
Next, we shall convert celsius temperature to Kelvin temperature. This can be achieved as shown below:
Temperature (K) = temperature (°C) + 273
T(K) = T (°C) + 273
Initial temperature (T1) = 9.9 °C
Initial temperature (T1) = 9.9 °C + 273 = 282.9 K
Final temperature (T2) = 9.3 °C
Final temperature (T2) = 9.3 °C + 273 = 282.3 K
Finally, we shall determine the new volume of the gas as follow:
Initial volume (V1) = 8 L
Initial temperature (T1) = 282.9 K
Final temperature (T2) = 282.3 K
Final volume (V2) =..?
V1/T1 = V2/T2
8/282.9 = V2/282.3
Cross multiply
282.9 x V2 = 8 x 282.3
Divide both side by 282.9
V2 = (8 x 282.3)/282.9
V2 = 7.98 L
Therefore, the new volume of the gas is 7.98 L