(-y^5)(8y^2) and (-7^5)(9y) and (-7^5)(-5)

asked Jan 10, 2021 19.8k views

4 votes

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4 votes

Answer:

$-8y^(25)\\-9y^6\\5y^5$

Explanation:

First one.

((-y)^5)(8y^(20))=-y^5*8y^(20)=-8y^(5+20)=-8y^(25)

Second one

((-y)^(5) )(9y)=-y^5*9y=-9y^(5+1)=-9y^6

and last one

((-y)^5)(-5)=-y^5*(-5)=5y^5

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