Question

Which equation shows a=bc^2+d solved for c

Answer 1

`\large \boxed{c=\pm \sqrt{(a-d)/(b)}}`

Explanation:

Hello,

`a=bc^2+d \\ \\ <=> a-d=bc^2+d-d=bc^2 \ \text{ subtract d }\\ \\ <=> c^2=(a-d)/(b) \ \text{ divide by b, assuming b is different from 0}\\ \\<=>\large \boxed{c=\pm \sqrt{(a-d)/(b)}} \ \ \text{ take the root of both parts}`

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