Question

How many mL of calcium hydroxide are required to neutralize 25.0 mL of 0.50 M
nitric acid?

Answer 1

6.5 mL

Step-by-step explanation:

Step 1: Write the balanced reaction

Ca(OH)₂ + 2 HNO₃ ⇒ Ca(NO₃)₂ + 2 H₂O

Step 2: Calculate the reacting moles of nitric acid

25.0 mL of 0.50 M nitric acid react.

`0.0250L * (0.50mol)/(L) = 0.013 mol`

Step 3: Calculate the reacting moles of calcium hydroxide

The molar ratio of Ca(OH)₂ to HNO₃ is 1:2. The reacting moles of Ca(OH)₂ are 1/2 × 0.013 mol = 6.5 × 10⁻³ mol

Step 4: Calculate the volume of calcium hydroxide

To answer this, we need the concentration of calcium hydroxide. Since the data is missing, let's suppose it is 1.0 M.

`6.5 * 10^(-3) mol * (1,000mL)/(1.0mol) = 6.5 mL`