Answer:
Mixing two concentrations for known amount of mixture
Explanation:
Let x = amount (ounces) of 18% solution
then
36-x = amount (ounces) of 9% solution
0.18x + 0.09(36-x) = .16(36)
0.18x + 3.24-.09x = 5.76
0.09x + 3.24 = 5.76
0.09x = 2.52
x = 28 ounces of 18% solution
amount of 9% solution:
36-x = 36-18 = 18 ounces
"prepare 36 ounces", means mass or weight.
Let u = ounces of 16%
Let v = ounces of 18%
(16u + 18v)/36=9
and u + v = 36
based on the above findings....
Mixing two concentrations for known amount of mixture