Question

Please help find these angle for me plz!

Answer 1

The remaining angle would be 40 degrees.

With triangles, all 3 angle values add up to 180, so we must apply that to this problem.

56+84=140

180-140=40

So our answer would be 40 degrees

Answer 2

<DEF = 40°

<EBF = <EDF = 56°

<DCF = <DEF =40°

<CAB = 84°

Explanation:

In triangle DEF, we have:

Given:

<EDF=56°

<EFD=84°

So, <DEF =180° - 56° - 84° =40° (sum of triangle angles is 180°)

____________

DE is a midsegment of triangle ACB

( since CD=DA(given)=>D is midpoint of [CD]

and BE = EA => E midpoint of [BA] )

According to midsegment Theorem,

. (DE) // (CB) "//"means parallel

. DE = CB/2 = FB =CF

___________

DEBF is a parm /parallelogram.

Proof: (DE) // (FB) [(DE) // (CB)]

AND DE = FB

Then, <EBF = <EDF = 56°

___________

DEFC is parm.

Proof: (DE) // (CF) [(DE) // (CB)]

And DE = CF

Therefore, <DCF = <DEF =40°

___________

In triangle ACB, we have:

<CAB =180 - <ACB - <ABC =180° - 40° - 56° =84° (sum of triangle angles is 180°)

`HOPE \: THIS \: HELPS.. GOOD \: LUCK!`