Question

What system shows the correct numbers to multiply by the coefficients in order to eliminate y from the first two

equations when applying the linear combination method?
50+ 2 = 0
2x – 3y = -19
o
3 (5+2g = 0)
2 (2x – 3y = -19)
o
–3 (5x + 2y = 0)
12 (2x – 3y = –19)
-2 (5x + 2y = 0)
5 (2x – 3y = -19)
s -2(5x + 2y = 0)
1-5 (2x - 3y = -19)

Answer 1

3 (5x+2y = 0)

2 (2x – 3y = -19)

Explanation:

5x+2y=0 (1)

2x-3y=-19 (2)

To eliminate y from the first two equation when applying the linear combination method

We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively

3(5x+2y=0)

2(2x-3y=-19)

We have,

15x+6y=0 (3)

4x-6y= -38 (4)

Add Equation (3) and (4)

19x=-38

x= -2

Substitute x= -2 into (1)

5x+2y=0

5(-2)+2y=0

-10+2y=0

-10= -2y

y=-10/-2

=5

y=5, x=-2