1 Answer

Jzd · Answer 1 · 2021-01-06T09:36:20+0000

Answer:

3

$d\in R,\hspace{5}d\\eq 0$

Explanation:

You can solve for any variable. From the first equation, let's solve for c :

$(c+1)/(d) =5\\\\c+1=5d\\\\c=5d-1$

Now, replace the value of c into the other equation:

$(30d)/(2c+2) \\\\(30d)/(2(5d-1)+2) \\$

Using distributive property

(30d)/(10d-2+2) =(30d)/(10d) =3

However, keep in mind that this is true for:

$d\in R,\hspace{5}d\\eq 0$

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