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In right triangle ABC, 2B is a right angle, AB = 48 units, BC = 55 units, and AC = 73 units.

literally please help me

In right triangle ABC, 2B is a right angle, AB = 48 units, BC = 55 units, and AC = 73 units-example-1
User Dirkjot
by
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2 Answers

5 votes

Answer:


csc (\theta)=(33)/(55)

Explanation:

Hello!

1) The cosecant function is the inverse the sine function. So we can write:


csc(\theta)=(1)/(sin(\theta))

2) The sine function is the side opposite angle to
\angle \theta over the hypotenuse:


sin(\theta)=(55)/(33)

3) So, remembering operations with fractions then the cosecant is:


csc \theta = (1)/((55)/(33) ) =1 * (33)/(55)


csc (\theta)=(33)/(55)

User Serhii Soboliev
by
4.5k points
1 vote

Answer:

73/55

Explanation:

The cosecant (csc) is one of the reciprocal functions:

csc(θ) = 1/sin(θ)

sec(θ) = 1/cos(θ)

cot(θ) = 1/tan(θ)

So, if we can find the sine, we can find the cosecant.

__

The mnemonic SOH CAH TOA reminds you that the sine is ...

Sin = Opposite/Hypotenuse

The above tells you that ...

Csc = 1/Sin = Hypotenuse/Opposite

The hypotenuse of your triangle is AC = 73. The side opposite angle θ is BC = 55. So, the ratio you want is ...

csc(θ) = 73/55

User Tokimon
by
4.5k points