Answer:
Student tickets cost $8 and adult tickets cost $5.
Explanation:
12a + 12y = 156
6a + 11y = 118
We can multiply the second equation by -2 to try and cancel out the a variable.
![12a + 12y = 156\\-12a - 22y = -236\\\\-10y = -80\\y = 8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5yqh9h560z3j0lur7ynykc1tdim2kfh64a.png)
Now that we know that the student tickets cost $8, we can substitute it into an equation to find the value of a, the adult tickets.
![12a + 12\cdot8 = 156\\12a+96=156\\12a=60\\a=5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s5zn1k4usdjs80vn6djgoz4e47cxnlf1f1.png)
So, adult tickets cost $5 and student tickets cost $8.
Hope this helped!