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Starting at home, Luis traveled uphill to the gift store for 50minutes at just 6 mph. He then traveled back home along the same path downhill at a speed of 12mph.

User Nuno G
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1 Answer

1 vote

Answer:

Average speed for the entire trip, both ways, is

(Total distance) divided by (total time) .

We don't know the distance from his house to the gift store,

and we don't know how long it took him to get back.

We'll need to calculate these.

-- On the trip TO the store, it took him 50 minutes, at 6 mph.

-- 50 minutes is 5/6 of an hour.

-- Traveling at 6 mph for 5/6 of an hour, he covered 5 miles.

-- The gift store is 5 miles from his house.

-- The total trip both ways was 10 miles.

-- On the way BACK home from the store, he moved at 12 mph.

-- Going 5 miles at 12 mph, it takes (5/12 hour) = 25 minutes.

Now we have everything we need.

Distance:

Going: 5 miles

Returning: 5 miles

Total 10 miles

Time:

Going: 50 minutes

Returning: 25 minutes

Total: 75 minutes = 1.25 hours

Average speed for the whole trip =

(total distance) / (total time)

= (10 miles) / (1.25 hours)

= (10 / 1.25) miles/hours

= 8 miles per hour

Explanation:

User Cellcore
by
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