Answer:
(1) Please find attached the graph of the data
(2) 160.396 m
(3) The correlation that exist is a straight line correlation
Explanation:
The given data are;
Distance, Time
(m), (s)
50, 6.1
100, 12
150, 18.3
200, 25.2
250, 31.7
(2)
Based on the linear regression formula, we have;
![b = (N\sum XY - \left (\sum X \right )\left (\sum Y \right ))/(N\sum X^(2) - \left (\sum X \right )^(2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/noghun929r7ornmp2dbz6sx3iw3um5x75e.png)
![b = (5 * 17215 - 93.3 * 750)/(5 * 2156.03 -8704.89) = 7.758](https://img.qammunity.org/2021/formulas/mathematics/high-school/9py9vke5axzijpnh0cy1ea35zrkhqeife5.png)
![a = (\sum Y - b\sum X)/(N)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ewwdvejo6xnirp9v37cm044wghnfk8de6e.png)
![a = (750 - 7.7581 * 93.3)/(5)= 5.234](https://img.qammunity.org/2021/formulas/mathematics/high-school/mmtj3l6dqy2wtk0w1yz1d5q35j0ifi9mof.png)
The line is
y = 7.7581×x+5.234
When t = 20 s, we have
y = 7.7581*20+5.234 = 160.396 m
(3) The correlation that exist is a straight line correlation