Question

Please help immediately ​

Answer 1

Answer:
`f'(1)=(4)/(2y+1)`

Explanation:

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given: 0 = 2x² - xy - y²

Derivative: 0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

y'(2y + 1) = 4x

`y'=(4x)/(2y+1)`

`\text{Substitute x = 1:}\quad y'(1)=(4)/(2y+1)`