Question

Solve 0 = 4x2+12x+9.

Select the equation that shows the correct
substitution of a, b, and c in the quadratic formula.
121 122 - 4(4309)
2(4)
X=
-12 + 122 +4(4)(9)
2(4)
o
-121 122 – 4(4)(9)
2(4)

Answer 1

Explanation:

Answer 2

The correct substitution of a, b, and c in the quadratic formula is given by

`$ x=(-12\pm√((12)^2-4(4)(9)))/(2(4)) $`

`x = - ( 3)/(2) \: and \: x = -( 3)/(2) \\\\`

The solutions of the given quadratic equation are real and equal.

Explanation:

The given quadratic equation is

`4x^2+12x+9 = 0`

The coefficients a, b and c are as follow:

`a = 4 \\\\b = 12\\\\c = 9`

The quadratic formula is given by

`$x=(-b\pm√(b^2-4ac))/(2a)$`

The correct substitution of a, b, and c in the quadratic formula is given by

`$ x=(-12\pm√((12)^2-4(4)(9)))/(2(4)) $`

Bonus:

The solution of this quadratic equation is given by

`x=(-12\pm√((144 - 144)))/(8) \\\\x=(-12\pm√(0))/(8) \\\\x=(-12\pm 0)/(8) \\\\x=(-12 + 0)/(8) \: and \: x=(-12 - 0)/(8)\\\\x= -( 3)/(2) \: and \: x = -( 3)/(2) \\\\`

Therefore, the solutions of the given quadratic equation are real and equal.