Question

The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. 5. Solve using the quadratic formula. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction What are the zeros of the function f(x) = x + 5 – 2x2? x = StartFraction negative 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction negative 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction

Answer 1

The CORRECT answer is A.

Explanation:

just did it.

Answer 2

To solve for the zeros of the function equate f(x) = 0

That's

- 2x² + x + 5 = 0

Using the quadratic formula

`x = \frac{ - b± \sqrt{ {b}^(2) - 4ac} }{2a}`

a = - 2 b = 1 c = 5

And from the question

b² - 4ac = 41

So we have

`x = ( - 1± √(41) )/(2( - 2)) = ( - 1± √(41) )/( - 4)`

`x = (1± √(41) )/(4)`

We have the final answer as

`x = (1 + √(41) )/(4) \: \: \: \: or \: \: \: \: x = (1 - √(41) )/(4)`

Hope this helps you