Question

the perimeter of football field in a rectangular form of a certain school is 296cm if the breath is2/3 of the length find the length field​

Answer 1

Turn the words into math symbols. This is an exercise in abstract substitution.

P = perimeter

Breath = Width

Perimeter = L+L+W+W

So…

P = 296

296 = L+L+W+ W

W=2/3* L

296 = L+L+2/3L+2/3L

296 = 2L+ 4/3 L

296 = 10/3 L

Multiply both sides by three…

888 = 10L

88.8 = L

Calculate in reverse to double check…

88.8+88.8+59.2+59.2 = 296

Answer 2

L = 29.6 cm

Explanation:

Let Length be L and Breadth be B

Condition 1:

`2(Length)+2(Breadth) = Perimeter`

Where Perimeter = 296 cm

=> 2L + 2B = 296

=> 2(L+B) = 296

Dividing both sides by 2

=> L + B = 148 ------------------(1)

Condition 2:

=> B =
`(2)/(3) L` -------------------------(2)

Putting Equation 2 in 1

=> L +
`(2)/(3) L` = 148

Multiplying both sides by 3

=> 3L + 2L = 148

=> 5L = 148

=> L = 148/5

=> L = 29.6 cm