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Rewrite the following equation in the form y = a(x - h)2 + k. Then, determine the x-coordinate of the minimum.

y = 2x2 - 32x + 56

The rewritten equation is y =
(x -
)2 +
.

The x-coordinate of the minimum is
.

User Cyprian
by
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1 Answer

1 vote

Answer:

Therefore the x - coordinate of the minimum is x = -8

Explanation:


y = 2x^2 + 32x + 56 = 2(x^2 + 16x ) + 56 = 2(x^2 + 16x +64 - 64) + 56 \\= 2(x^2 + 16x +64) - 128 + 56 = 2(x+8)^2 - 72

Therefore the x - coordinate of the minimum is x = -8

User Vojislav Kovacevic
by
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