Question

What is the molarity of a solution formed by dissolving 55.43 grams of CaF- in 3.87 L of solution?

Answer 1

0.24mol/L

Step-by-step explanation:

The molarity of a solution is also its Concentration (C)

C =
`(Moles(n))/(Volume (V))`

mass of CaF = 55.43g

volume = 3.87L

Molar mass of CaF = 58.99g/mol

moles =
`(55.43g)/(58.99g/mol)`

=0.94mol

∴ Concentration =
`(0.94mol)/(3.87L)`

= 0.24mol/L