x² - 8x + 12 = 0
First of all we need to find the roots
Δ = b² - 4.a.c
Δ = (-8)² - 4 . 1 . 12
Δ = 64 - 4. 1 . 12
Δ = 16
Has 2 real roots
x = (-b +- √Δ)/2a
x' = (--8 + √16)/2.1
x'' = (--8 - √16)/2.1
x' = 12 / 2
x'' = 4 / 2
x' = 6
x'' = 2
So our equation can be solved with x = 6 and x = 2, therefore we can create two other equations with the same roots
x - 6 = 0
and
x - 2 = 0