231k views
0 votes
If $y^2= 36$, what is the greatest possible value of $y^3$?

User Lavel
by
5.7k points

1 Answer

2 votes

Answer:

216

Explanation:

y = ±√36 = ±6

y³ = (±6)³ = ±216

The largest of these values is 216, the greatest possible value of y.

User Mwfire
by
5.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.