If $y^2= 36$, what is the greatest possible value of $y^3$?

asked Jun 16, 2021 231k views

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by Lavel

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Answer:

216

Explanation:

y = ±√36 = ±6

y³ = (±6)³ = ±216

The largest of these values is 216, the greatest possible value of y.

Mwfire answered Jun 20, 2021

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