71.0k views
5 votes
The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)

User RodolfoAP
by
8.6k points

1 Answer

4 votes

Answer:

y + 2 =
(2)/(3)(x - 1)

Explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 =
(2)/(3)(x - 3) ← is in point- slope form

with slope m =
(2)/(3)

Parallel lines have equal slopes, thus equation of parallel line

with m =
(2)/(3) and (a, b) = Q(1, - 2) is

y - (- 2) =
(2)/(3)(x - 1) , that is

y + 2 =
(2)/(3)(x - 1)

User Joey Gennari
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories