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The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)

User RodolfoAP
by
4.6k points

1 Answer

4 votes

Answer:

y + 2 =
(2)/(3)(x - 1)

Explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 =
(2)/(3)(x - 3) ← is in point- slope form

with slope m =
(2)/(3)

Parallel lines have equal slopes, thus equation of parallel line

with m =
(2)/(3) and (a, b) = Q(1, - 2) is

y - (- 2) =
(2)/(3)(x - 1) , that is

y + 2 =
(2)/(3)(x - 1)

User Joey Gennari
by
4.2k points