Question

Find the 10th term of a geometric sequence whose first tow terms are 2 and -8

Answer 1

-524288

Step by step

so use the formula

ar^n-1

so

a is first term

r is common ratio

n is number of terms

so

get r which is -8/2=-4

then apply

2×(-4^9)=answer

not sure

Answer 2

t10 = - 2¹⁹= -524288

Explanation:

t1=2

t2=-8

r=t2/t1=-8/2=-4

t10=t1*r⁹

t10=2*(-4)⁹= -2*(2²)⁹

t10= -2¹⁹= -524288