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A group of students were given a spelling test the table shows their mark Mark: 6,7,8,9,10 frequency:5,4,7,10,4 a) work out the range of the marks. B)how many students are in a group C) work out the mean mark of the group

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Answer: From the information given, Mark: 6,7,8,9,10 frequency:5,4,7,10,4 a) Range = highest mark - lowest markRange = 10 - 6 = 4b) The number of students in the group is the sum of the frequency. Therefore, Number of students = 5 + 4 + 7 + 10 + 4 = 30 studentsc) Mean mark = (mark × frequency)/total frequency[(6 × 5) + (7 × 4) + (8 × 7) + (9 × 10) + 10 × 4)]/ 30Mean mark = (30 + 28 + 56 + 90 + 40)/30 = 244/30Mean mark = 8.1

Explanation:

User Vasisualiy
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Answer:

Explanation:

From the information given,

Mark: 6,7,8,9,10

frequency:5,4,7,10,4

a) Range = highest mark - lowest mark

Range = 10 - 6 = 4

b) The number of students in the group is the sum of the frequency. Therefore,

Number of students = 5 + 4 + 7 + 10 + 4 = 30 students

c) Mean mark = (mark × frequency)/total frequency

[(6 × 5) + (7 × 4) + (8 × 7) + (9 × 10) + 10 × 4)]/ 30

Mean mark = (30 + 28 + 56 + 90 + 40)/30 = 244/30

Mean mark = 8.1

User Asfar Irshad
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