Question

The base of an isosceles triangle is 4/3. The perimeter of the triangle is 4 2/15. What is the length of either of the remaining sides?

Answer 1

The answer to your question is 1
`(2)/(5)`

Explanation:

Data

base = 4/3

Perimeter = 4 2/15

length of the sides = ?

Process

1.- Convert the perimeter into an improper fraction

`4(2)/(15) = (60 + 2)/(15) = (62)/(15)`

2.- Subtract 4/3 from 62/15

`(62)/(15) - (4)/(3)`

`(62)/(15) - (20)/(15)` Multiply 4/3 by 5

`(42)/(15)`

3.- Divide the result by 2 to find the length of one side

`(42)/(15) / (2)/(1)`

4.- Result

`(42)/(30)`

-Simplify

`(7)/(5)` or 1 2/5