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an organisms population in the year 2000 was about 9 billion and was increasing with a double time of 20 years. Suppose the population continued this growth pattern from the year 2000 into the future. Complete part a through d

User David West
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Answer:

For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:


18 =9(b)^20

And if we solve for b we got:


2 = b^20


2^(1/20)= b

And then the model would be:


y(t) = 9 (2)^{(t)/(20)}

Where y is on billions and t the time in years since 2000.

And for this equation is possible to find the population any year after 2000

Explanation:

For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:


18 =9(b)^20

And if we solve for b we got:


2 = b^20


2^(1/20)= b

And then the model would be:


y(t) = 9 (2)^{(t)/(20)}

Where y is on billions and t the time in years since 2000.

And for this equation is possible to find the population any year after 2000

User Joshua Drake
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5.2k points