Question

Solve for x -8x+44≥60 and -4x+50<58 Thanks! :)

Answer 1

1.
`x \leqslant - 2`

2.
`x \: > 2`

Explanation:

1.
`- 8x + 44 \geqslant 60`

Move constant to R.H.S and change its sign

`- 8x \geqslant 66 - 44`

Subtract the numbers

`- 8x \geqslant 16`

Divide both sides of the inequality by -8 and flip the inequality sign

`x \leqslant - 2`

2.
`- 4x + 50 < 58`

Move constant to the R.H.S and change its sign

`- 4x < 58 - 50`

Subtract the numbers

`- 4x < 8`

Divide both sides of the inequality by - 4 and flip the inequality sign

`x > - 2`

Hope this helps...

Best regards!!

Answer 2

Explanation:

- 8x + 44 ≥ 60

Subtract 44 from both sides

- 8x + 44 - 44 ≥ 60 - 44

- 8x ≥ 16

Divide both sides by -8 and flip the inequality sign

-8x/-8 ≤ 16/-8

x ≤ -2

x = { ......... -4,-3,-2}

2) -4x + 50 < 58

Subtract 50from both sides

-4x + 50 -50 < 58- 50

-4x < 8

Divide both sides by -4 and flip the inequality sign

-4x/-4 > 8/-4

x > -2

x= {-1, 0 , 1 , 2....... }