Question

Assuming a Stop-and-Wait system, if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandwidth-delay product? If the data packets are 2500 bits in length, what is the utilization?

Answer 1

Bandwidth delay product = 2500 Kbits

Utilization = 0.02%

Step-by-step explanation:

We proceed as follows;

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

The system can send 12500 Kbits during the time it takes for the data to go from the sender to the receiver and then back again.

However, the system sends only 2500 bits.

The the link utilization =

2500/(12500 x 10^3) = 0.02%