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In one region, the September energy consumption levels for single-family homes are found to be normally distributed with a mean of 1050 kWh and a standard deviation of 218 kWh. Find the energy consumption level for the 45th percentile. Group of answer choices

User Eulerfx
by
8.1k points

1 Answer

3 votes

Answer: 1022.75 kWh.

Explanation:

Given: In one region, the September energy consumption levels for single-family homes are found to be normally distributed with a mean of 1050 kWh and a standard deviation of 218 kWh.

i.e.
\mu=1050\ kWh and
\sigma=218\ kWh

Let X denote energy consumption levels for random single-family homes and x be the energy consumption level for the 45th percentile.

Then,
P(X<x)=0.45

From z-table,
P(z<-0.125)=0.45

Also,
z=(x-\mu)/(\sigma)


\Rightarrow\ -0.125=(x-1050)/(218)\\\\\Rightarrow\ x=-0.125*218+1050=1022.75

Hence, the energy consumption level for the 45th percentile is 1022.75 kWh.

User Bumpy
by
8.5k points
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