Question

Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equals cotangent (5 Upper B plus 10 degrees )

Answer 1

Explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan (90 - 5B - 10 )

(3B-32 ) = (90 - 5B - 10 )

8B = 32 + 80

B = 14° .